Limits, Continuity, Differentiability
Short Notes
Limits
The limit of a function f(x) as x approaches a point c is the value that f(x) approaches as x gets arbitrarily close to c.
- Left-hand limit (LHL): \(\lim_{x \to c^-} f(x)\)
- Right-hand limit (RHL): \(\lim_{x \to c^+} f(x)\)
- Limit exists iff LHL = RHL
Continuity
A function f(x) is continuous at x = c if:
- f(c) is defined
- \(\lim_{x \to c} f(x)\) exists
- \(\lim_{x \to c} f(x) = f(c)\)
Differentiability
A function is differentiable at x = c if: $\(f'(c) = \lim_{h \to 0} \frac{f(c+h) - f(c)}{h}\)$ exists.
Key Relationship: $\(\text{Differentiable} \Rightarrow \text{Continuous} \Rightarrow \text{Limit exists}\)$ (Converse is NOT always true!)
Key Theories & Formulas
1. Standard Limits
| Limit | Value |
|---|---|
| \(\lim_{x \to 0} \frac{\sin x}{x}\) | 1 |
| \(\lim_{x \to 0} \frac{\tan x}{x}\) | 1 |
| \(\lim_{x \to 0} \frac{1 - \cos x}{x^2}\) | \(\frac{1}{2}\) |
| \(\lim_{x \to 0} \frac{e^x - 1}{x}\) | 1 |
| \(\lim_{x \to 0} \frac{\ln(1+x)}{x}\) | 1 |
| \(\lim_{x \to 0} \frac{a^x - 1}{x}\) | \(\ln a\) |
| \(\lim_{x \to 0} (1 + x)^{1/x}\) | \(e\) |
| \(\lim_{x \to \infty} (1 + \frac{1}{x})^x\) | \(e\) |
| \(\lim_{x \to 0} \frac{\sin^{-1} x}{x}\) | 1 |
| \(\lim_{x \to 0} \frac{\tan^{-1} x}{x}\) | 1 |
2. L'Hôpital's Rule
For indeterminate forms \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\): $\(\lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}\)$
Other indeterminate forms: \(0 \cdot \infty\), \(\infty - \infty\), \(0^0\), \(1^\infty\), \(\infty^0\) (convert to \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\))
3. Types of Discontinuity
| Type | Description |
|---|---|
| Removable | Limit exists but ≠ f(c), or f(c) undefined |
| Jump | LHL ≠ RHL (both finite) |
| Infinite | At least one limit is infinite |
| Oscillatory | Limit doesn't exist (e.g., \(\sin(1/x)\) at x=0) |
4. Derivative Formulas
| Function | Derivative |
|---|---|
| \(x^n\) | \(nx^{n-1}\) |
| \(e^x\) | \(e^x\) |
| \(a^x\) | \(a^x \ln a\) |
| \(\ln x\) | \(\frac{1}{x}\) |
| \(\sin x\) | \(\cos x\) |
| \(\cos x\) | \(-\sin x\) |
| \(\tan x\) | \(\sec^2 x\) |
5. Non-Differentiable Cases
A function is NOT differentiable at x = c if:
- There's a corner/cusp (e.g., |x| at x = 0)
- There's a vertical tangent
- There's a discontinuity
- Left and right derivatives differ
Example Problems
Problem 1: Evaluate \(\lim_{x \to 0} \frac{\sin 5x}{3x}\)
Solution: $\(\lim_{x \to 0} \frac{\sin 5x}{3x} = \lim_{x \to 0} \frac{\sin 5x}{5x} \cdot \frac{5}{3} = 1 \cdot \frac{5}{3} = \mathbf{\frac{5}{3}}\)$
Problem 2: Check continuity of \(f(x) = \begin{cases} \frac{\sin x}{x} & x \neq 0 \\ k & x = 0 \end{cases}\) at x = 0
Solution:
- \(\lim_{x \to 0} \frac{\sin x}{x} = 1\)
- For continuity: k = 1
Problem 3: Is \(f(x) = |x|\) differentiable at x = 0?
Solution:
- Left derivative: \(\lim_{h \to 0^-} \frac{|h| - 0}{h} = \lim_{h \to 0^-} \frac{-h}{h} = -1\)
- Right derivative: \(\lim_{h \to 0^+} \frac{|h| - 0}{h} = \lim_{h \to 0^+} \frac{h}{h} = 1\)
- Left ≠ Right → Not differentiable at x = 0
Hardest GATE Questions
Topic: L'Hôpital's Rule with \(1^\infty\) Form
Question (GATE 2018 Style): Evaluate \(\lim_{x \to 0} (\cos x)^{1/x^2}\)
Solution:
- Form: \(1^\infty\) (indeterminate)
- Let \(y = (\cos x)^{1/x^2}\)
- \(\ln y = \frac{\ln(\cos x)}{x^2}\)
-
Apply L'Hôpital's Rule: $\(\lim_{x \to 0} \frac{\ln(\cos x)}{x^2} = \lim_{x \to 0} \frac{-\tan x}{2x} = -\frac{1}{2}\)$
-
\(\ln y = -\frac{1}{2}\)
- \(y = e^{-1/2} = \mathbf{\frac{1}{\sqrt{e}}}\)
Why it's hard: Requires recognizing \(1^\infty\) form and using logarithmic transformation.
Topic: Differentiability at a Point
Question (GATE 2016 Variant): For what value of n is \(f(x) = x^n \sin(1/x)\) for \(x \neq 0\), and \(f(0) = 0\), differentiable at x = 0?
Solution:
-
Check derivative at x = 0: $\(f'(0) = \lim_{h \to 0} \frac{h^n \sin(1/h)}{h} = \lim_{h \to 0} h^{n-1} \sin(1/h)\)$
-
For this limit to exist:
- \(|h^{n-1} \sin(1/h)| \leq |h|^{n-1}\)
- Need \(n - 1 > 0\), i.e., n > 1
- For n = 2: limit = 0 (derivative exists)
- For n = 1: limit oscillates (derivative doesn't exist)
Answer: \(\mathbf{n > 1}\) (or n ≥ 2 for integer n)
Topic: Continuity with Floor Function
Question: Find the number of points where \(f(x) = [x] + \sqrt{x - [x]}\) is discontinuous in [0, 3].
Solution:
- \(f(x) = [x] + \sqrt{\{x\}}\) where {x} is the fractional part
- \(\sqrt{\{x\}}\) is continuous everywhere
- [x] is discontinuous at integers: 1, 2, 3
- At x = 1: LHL = 0 + 1 = 1, RHL = 1 + 0 = 1 → Continuous
- At x = 2: LHL = 1 + 1 = 2, RHL = 2 + 0 = 2 → Continuous
- At x = 3: LHL = 2 + 1 = 3, RHL = 3 + 0 = 3 → Continuous
- 0 discontinuities in [0, 3]